Problem 57

sqrt2 = (1,1):[(2*n+d,n+d)|(d,n)<-sqrt2]
p057 = length.filter (f.snd).zip [..1000] $sqrt2
where f (x,y) = (length.show)x > (length.show) y

そのまんまですなぁ

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Newer// Problem 56
Older// Problem 47